Python code

 # List of documents

# Each outer list represents one document

# Each document contains one or more sentences

documents = [

    ["Hello world", "Hello Python"],

    ["Python is great", "Hello again"],

    ["Enjoy coding in Python"]

]

# Dictionary to store the inverted index

# Key   -> word

# Value -> list of document IDs where the word appears

index = {}

# Loop through each document with its index (document ID)

for doc_id, doc in enumerate(documents):

    # Join all sentences in the current document into a single string

    # Convert text to lowercase to avoid case-sensitive duplicates

    text = " ".join(doc).lower()

    

    # Split the text into individual words using space as delimiter

    words = text.split()

    

    # Loop through each word in the current document

    for word in words:

        

        # If the word is not already in the index,

        # create a new entry with an empty list

        if word not in index:

            index[word] = []

        

        # Add the document ID only if it is not already present

        # This avoids duplicate document IDs for the same word

        if doc_id not in index[word]:

            index[word].append(doc_id)

# Print the final inverted index

print(index)

output:

{

    'hello': [0, 1],

    'world': [0],

    'python': [0, 1, 2],

    'is': [1],

    'great': [1],

    'again': [1],

    'enjoy': [2],

    'coding': [2],

    'in': [2]

}

=========================================

# Input data: a list of tuples

# Each tuple contains (name, score)

data = [('Alice', 88), ('Bob', 72), ('Alice', 91), ('Bob', 85)]

# Function to group scores by name

def group_scores(data):

    

    # Dictionary to store the grouped result

    # Key   -> name (e.g., 'Alice', 'Bob')

    # Value -> list of scores for that name

    result = {}

    

    # Loop through each (name, score) pair in the input data

    for name, score in data:

        

        # If the name is not already a key in the dictionary,

        # create a new key with an empty list

        if name not in result:

            result[name] = []

        

        # Add the score to the list for the corresponding name

        result[name].append(score)

    

    # Return the dictionary containing grouped scores

    return result

# Call the function and print the result

print(group_scores(data))

output:

{

    'Alice': [88, 91],

    'Bob': [72, 85]

}

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